Applications Of Derivatives Question 21
Question: What is the slope of the tangent to the curve $ x=t^{2}+3t-8,y=2t^{2}-2t-5att=2 $ -
Options:
A) 7/6
B) 6/7
C) 1
D) 5/6
Show Answer
Answer:
Correct Answer: B
Solution:
[b] $ \frac{dx}{dt}=2t+3,\frac{dy}{dt}=4t-2 $
$ \frac{dy}{dx}=\frac{dy/dt}{dx/dt}=\frac{4t-2}{2t+3} $ slope at $ t=2=\frac{dy}{dx}/t=2=\frac{4(2)-2}{2(2)+3}=\frac{6}{7} $
BETA
