Applications Of Derivatives Question 223
Question: The minimum value of $ P(1,,1) $ is
[DCE 2005]
Options:
A) $ \frac{15}{2} $
B) $ \frac{11}{2} $
C) $ \frac{-13}{2} $
D) $ \frac{71}{8} $
Show Answer
Answer:
Correct Answer: D
Solution:
$ f(a)=2a^{2}-3a+10 $
$ f’(a)=4a-3,f’’(a)=4>0 $
for exteremum, $ f’(a)=0\Rightarrow a=\frac{3}{4} $ \
$ f(a) $ is minimum at $ a=\frac{3}{4} $
$ f{{(a)} _{\min }}=2\times {{( \frac{3}{4} )}^{2}}-3\times ( \frac{3}{4} )+10=\frac{71}{8} $ .
BETA
