Applications Of Derivatives Question 239

Question: The function $ f(x)=x^{3}-3x^{2}-24x+5 $ is an increasing function in the interval given below

[MP PET 1998]

Options:

A) $ (-\infty ,,-2)\cup (4,\infty ) $

B) $ (-2,\infty ) $

C) (-2, 4)

D) $ (-\infty ,,4) $

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Answer:

Correct Answer: A

Solution:

$ f(x)=x^{3}-3x^{2}-24x+5 $ For increasing, $ f’(x)>0 $ , $ 3x^{2}-6x-24>0 $

therefore $ x^{2}-2x-8>0 $

$ x^{2}-4x+2x-8>0 $

therefore $ (x+2)(x-4)>0 $

$ x\in (-\infty ,,-2)\cup (4,\infty ) $ .