Applications Of Derivatives Question 250
Question: A particle moves in a straight line so that its velocity at any point is given by $ v^{2}=a+bx $ , where $ a,b\ne 0 $ are constants. The acceleration is
[MP PET 1989]
Options:
A) Zero
B) Uniform
C) Non-uniform
D) Indeterminate
Show Answer
Answer:
Correct Answer: B
Solution:
$ v^{2}=a+bx $
therefore $ 2v\frac{dv}{dt}=b\frac{dx}{dt} $
therefore $ 2v\frac{dv}{dt}=bv $
therefore $ \frac{dv}{dt}=\frac{b}{2} $
Hence acceleration is constant or uniform.
BETA
