Applications Of Derivatives Question 260

Question: The function $ f(x)=\frac{\log x}{x} $ is increasing in the interval

[UPSEAT 2001]

Options:

A) $ (1,,2e) $

B) (0,e)

C) (2, 2e)

D) (1/e, 2e)

Show Answer

Answer:

Correct Answer: B

Solution:

$ f(x)=\frac{\log x}{x} $

$ {f}’(x)=\frac{1}{x^{2}}-\frac{\log x}{x^{2}}=\frac{1-\log x}{x^{2}} $ For $ f(x) $ to be increasing, $ {f}’(x)>0 $

therefore $ 1-\log x>0 $

therefore $ 1>\log x $

therefore $ e>x $ \ $ f(x) $ is increasing in the interval $ (0,,e) $ .