Applications Of Derivatives Question 285
Question: A function is matched below against an interval where it is supposed to be increasing. Which of the following pairs is incorrectly matched-
[AIEEE 2005]
Options:
A) Interval Function $ ( -\infty ,,\frac{1}{3} ] $ $ 3x^{2}-2x+1 $
B) (- ¥, - 4] $ x^{3}+6x^{2}+6 $
C) (- ¥, ¥) $ x^{3}-3x^{2}+3x+3 $
D) [2, ¥) $ 2x^{3}-3x^{2}-12x+6 $
Show Answer
Answer:
Correct Answer: A
Solution:
$ f(x)=3x^{2}-2x+1 $ , $ {f}’(x)=6x-2\ge 0 $
therefore $ x\ge \frac{1}{3} $
Option is incorrect. Checking other function similarly we find that they are correctly matched.
BETA
