Applications Of Derivatives Question 288
Question: Local maximum and local minimum values of the function $ (x-1){{(x+2)}^{2}} $ are
Options:
A) - 4, 0
B) 0, - 4
C) 4, 0
D) None of these
Show Answer
Answer:
Correct Answer: B
Solution:
$ f’(x)=2(x-1)(x+2)+{{(x+2)}^{2}}=3x^{2}+6x $
$ f’(x)=0 $
therefore $ x=0,,-2 $
$ f(-2)=(-2-1){{(-2+2)}^{2}}=0 $ (Maximum value) and $ f(0)=(0-1){{(0+2)}^{2}}=-4 $ (Minimum value).
BETA
