Applications Of Derivatives Question 340
Question: The function $ f(x)=2x^{3}-3x^{2}-12x+4 $ has
[DCE 2002]
Options:
A) No maxima and minima
B) One maximum and one minimum
C) Two maxima
D) Two minima
Show Answer
Answer:
Correct Answer: B
Solution:
$ f(x)=2x^{3}-3x^{2}-12x+4 $
$ {f}’(x)=6x^{2}-6x-12 $
Now $ {f}’(x)=0 $
therefore $ x^{2}-x-2=0 $
therefore $ x=2,,-1 $
Now $ {f}’’(x)=12x-6 $
therefore $ {f}’’(2)=+ve $ , $ {f}’’(-1)=-ve $ \Given function has one maximum and one minimum.
BETA
