Applications Of Derivatives Question 368
Question: A ball thrown vertically upwards falls back on the ground after 6 second. Assuming that the equation of motion is of the form $ s=ut-4.9t^{2} $ , where s is in metre and t is in second, find the velocity at $ t=0 $
Options:
A) $ 0,m/s $
B) 1 m/s
C) 29.4 m/s
D) None of these
Show Answer
Answer:
Correct Answer: C
Solution:
Velocity of ball (v) = $ \frac{ds}{dt}= $
$ u-9.8t $
Here terminal velocity $ v=0 $ and $ t=3,sec $
$ u=9.8(3)=29.4m/sec $ .
BETA
