Applications Of Derivatives Question 375
Question: The motion of stone thrown up vertically is given by $ s=13.8t-4.9t^{2} $ , where s is in metre and t is in seconds. Then its velocity at $ t=1 $ second is
Options:
A) 3 m/s
B) 5 m/s
C) 4 m/s
D) None of these
Show Answer
Answer:
Correct Answer: C
Solution:
$ s=13.8t-4.9t^{2} $
Its velocity $ v=\frac{ds}{dt}=13.8-9.8t $
Hence $ {{( \frac{ds}{dt} )} _{t=1}}=13.8-9.8\times 1=4.0=4m/\sec . $
BETA
