Applications Of Derivatives Question 382
Question: For which interval, the function $ \frac{x^{2}-3x}{x-1} $ satisfies all the conditions of Rolle’s theorem
[MP PET 1993]
Options:
A) [0, 3]
B) [- 3, 0]
C) [1.5, 3]
D) For no interval
Show Answer
Answer:
Correct Answer: D
Solution:
Here $ f(x)=\frac{x^{2}-3x}{x-1} $
therefore $ -\sin c=-\frac{2}{\pi }\Rightarrow c={{\sin }^{-1}}( \frac{2}{\pi } ) $
Obviously, it is not differentiable at $ x=1 $ i.e., in $ (0,3) $ Also $ f(a)=f(b) $ does not hold for $ [-3,,0] $ and $ [1.5, 3] $
Hence, the answer is.
BETA
