Applications Of Derivatives Question 395
Question: If from mean value theorem, $ f’(x_1)=\frac{f(b)-f(a)}{b-a} $ , then
[MP PET 1999]
Options:
A) $ a<x_1\le b $
B) $ a\le x_1<b $
C) $ a<x_1<b $
D) $ a\le x_1\le b $
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Answer:
Correct Answer: C
Solution:
According to mean value theorem,
In interval [a, b] for f (x) $ \frac{f(b)-f(a)}{b-a}=f’(c) $ , where $ a<c<b $
$ \therefore a<x_1<b $ .
BETA
