Applications-Of-Derivatives Question 442
Question: The points on the curve $ y=12x-x^{3} $ at which the gradient is zero are
[MP PET 1999]
Options:
A) (0, 2), (2,16)
B) (0, ? 2), (2, ? 16)
C) (2, ?16), (? 2, 16)
D) (2, 16), (? 2, ? 16)
Show Answer
Answer:
Correct Answer: D
Solution:
$ \frac{dy}{dx}=12-3x^{2}=0\Rightarrow x=\pm 2 $ Hence points are (2,16) and (?2, ?16).
BETA
