[MNR 1995; Pb. CET 2000; Karnataka CET 2002]
A) Always increases
B) Always decreases
C) Never decreases
D) Sometimes increases and sometimes decreases
Correct Answer: A
$ y=\tan x-x\Rightarrow \frac{dy}{dx}={{\sec }^{2}}x-1={{\tan }^{2}}x\ge 0 $ .
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