Binomial Theorem And Its Simple Applications Question 111
Question: The least remainder when $ 17^{30} $ is divided by 5 is
[Karnataka CET 2003]
Options:
A) 1
B) 2
C) 3
D) 4
Show Answer
Answer:
Correct Answer: D
Solution:
- 17 = 2 (mod 5) $ {{(17)}^{5}}={{(2)}^{5}},(\text{mod 5)} $ = 2 (mod 5)
therefore $ {{(17^{5})}^{6}}={{(2)}^{6}} $ (mod 5)
therefore $ {{(17)}^{30}}=4 $ (mod 5)
Hence required remainder = 4.
BETA
