Binomial Theorem And Its Simple Applications Question 124
Question: If $ p(n)=n^{2}+n, $ $ \forall ,n\in N $ , then p(n) is
Options:
A) even positive integer
B) prime number
C) odd integer
D) multiple of 4
Show Answer
Answer:
Correct Answer: A
Solution:
- [a] $ P(n)=n^{2}+n: $
$ P(1)=1+1=2; $
$ P(2)=2^{2}+2=6; $
$ P(3)=3^{2}+3=12 $
We observe that $ \forall n\in N, $
$ P(n) $ is always an even positive integer.
BETA
