Binomial Theorem And Its Simple Applications Question 172
Question: The value of $ ^{15}C_0^{2}{{-}^{15}}C_1^{2}{{+}^{15}}C_2^{2}-….{{-}^{15}}C_15^{2} $ is
[MP PET 1996]
Options:
A) 15
B) - 15
C) 0
D) 51
Show Answer
Answer:
Correct Answer: C
Solution:
- As we know that $ ^{n}C_0-{{,}^{n}}C_1^{2}+{{,}^{n}}C_2^{2}-{{,}^{n}}C_3^{2}+…+{{(-1)}^{n}}.{{,}^{n}}C_n^{2}=0 $ , (if n is odd) and in the question n=15 (odd).