Binomial Theorem And Its Simple Applications Question 58
Question: $ \frac{C_1}{C_0}+2\frac{C_2}{C_1}+3\frac{C_3}{C_2}+….+15\frac{C_{15}}{C_{14}}= $
[IIT 1962]
Options:
A) 100
B) 120
C) $ -120 $
D) None of these
Show Answer
Answer:
Correct Answer: B
Solution:
- We know that $ \frac{C_1}{C_0}+2\frac{C_2}{C_1}+3\frac{C_3}{C_2}+….+n.\frac{C_{n}}{{C_{n-1}}}=\frac{n(n+1)}{2} $ Putting n=15, then $ \frac{15\times (15+1)}{2}=120 $ .
BETA
