Binomial Theorem And Its Simple Applications Question 91
Question: If n is a natural number, then
Options:
A) $ 1^{2}+2^{2}+…+n^{2}<\frac{n^{3}}{3} $
B) $ 1^{2}+2^{2}+…+n^{2}=\frac{n^{3}}{3} $
C) $ 1^{2}+2^{2}+…+n^{2}>n^{3} $
D) $ 1^{2}+2^{2}+…+n^{2}>\frac{n^{3}}{3} $
Show Answer
Answer:
Correct Answer: D
Solution:
- [d] By taking option (d) When n = 1 then $ 1>\frac{1}{3} $ [true] When n = 2 then $ 5>\frac{8}{3}, $ [true] When n = 3 then $ 14>9, $ [true] When n = 4 then $ 30>\frac{64}{3}=21.33 $ [true]