Circle And System Of Circles Question 115
Question: Two given circles $ x^{2}+y^{2}+ax+by+c=0 $ and $ x^{2}+y^{2}+dx+ey+f=0 $ will intersect each other orthogonally, only when
Options:
A) $ a+b+c=d+e+f $
B) $ ad+be=c+f $
C) $ ad+be=2c+2f $
D) $ 2ad+2be=c+f $
Show Answer
Answer:
Correct Answer: C
Solution:
From Condition for orthogonal intersection, $ \frac{ad}{2}+\frac{be}{2}=c+f $
BETA
