Circle And System Of Circles Question 121
Question: If one end of a diameter of the circle $ x^{2}+y^{2}-4x-6y+11=0 $ be (3, 4), then the other end is
[MP PET 1986; BIT Ranchi 1991]
Options:
A) (0, 0)
B) (1, 1)
C) (1, 2)
D) (2, 1)
Show Answer
Answer:
Correct Answer: C
Solution:
Centre is (2, 3). One end is (3, 4). $ P_2 $ divides the join of $ P_1 $ and O in ratio of 2 : 1.
Hence $ P_2 $ is $ ( \frac{4-3}{2-1},\ \frac{6-4}{2-1} )\equiv (1,\ 2) $ .
BETA
