Circle And System Of Circles Question 125
Question: The equation of the circle passing through the origin and cutting intercepts of length 3 and 4 units from the positive axes, is
Options:
A) $ x^{2}+y^{2}+6x+8y+1=0 $
B) $ x^{2}+y^{2}-6x-8y=0 $
C) $ x^{2}+y^{2}+3x+4y=0 $
D) $ x^{2}+y^{2}-3x-4y=0 $
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Answer:
Correct Answer: D
Solution:
Obviously the centre of the circle is $ ( \frac{3}{2},\ 2 ) $ . Therefore, the equation of circle is $ {{( x-\frac{3}{2} )}^{2}}+{{(y-2)}^{2}}={{( \frac{5}{2} )}^{2}}\Rightarrow x^{2}+y^{2}-3x-4y=0 $ .
BETA
