Circle And System Of Circles Question 14
Question: The equation of the tangent to the circle $ x^{2}+y^{2}-2x-4y-4=0 $ which is perpendicular to $ 3x-4y-1=0 $ , is
Options:
A) $ 4x+3y-5=0 $
B) $ 4x+3y+25=0 $
C) $ 4x-3y+5=0 $
D) $ 4x+3y-25=0 $
Show Answer
Answer:
Correct Answer: D
Solution:
Tangent is of form $ 4x+3y+c=0 $ . From condition of tangency to the circle, we get $ c=-25 $ .
Hence equation is $ 4x+3y-25=0 $ .
BETA
