Circle And System Of Circles Question 141
Question: The equation of circle whose diameter is the line joining the points (-4, 3) and (12, -1) is
[IIT 1971; RPET 1984, 87, 89; MP PET 1984; Roorkee 1969; AMU 1979]
Options:
A) $ x^{2}+y^{2}+8x+2y+51=0 $
B) $ x^{2}+y^{2}+8x-2y-51=0 $
C) $ x^{2}+y^{2}+8x+2y-51=0 $
D) $ x^{2}+y^{2}-8x-2y-51=0 $
Show Answer
Answer:
Correct Answer: D
Solution:
Required equation is $ (x-x_1)(x-x_2)+(y-y_1)(y-y_2)=0 $
$ (x+4)(x-12)+(y-3)(y+1)=0 $
$ x^{2}+y^{2}-8x-2y-51=0 $ .
BETA
