Circle And System Of Circles Question 144
Question: The equation of the circle concentric with the circle $ x^{2}+y^{2}+8x+10y-7=0 $ and passing through the centre of the circle $ x^{2}+y^{2}-4x-6y=0 $ is
Options:
A) $ x^{2}+y^{2}+8x+10y+59=0 $
B) $ x^{2}+y^{2}+8x+10y-59=0 $
C) $ x^{2}+y^{2}-4x-6y+87=0 $
D) $ x^{2}+y^{2}-4x-6y-87=0 $
Show Answer
Answer:
Correct Answer: B
Solution:
Centre is $ (-4,\ -5) $ and passes through (2, 3).
BETA
