Circle And System Of Circles Question 148
Question: The equations of the circles touching both the axes and passing through the point (1, 2) are
Options:
A) $ x^{2}+y^{2}-2x-2y+1=0,\ x^{2}+y^{2}-10x-10y+25=0 $
B) $ x^{2}+y^{2}-2x-2y-1=0,\ x^{2}+y^{2}-10x-10y-25=0 $
C) $ x^{2}+y^{2}+2x+2y+1=0,\ x^{2}+y^{2}+10x+10y+25=0 $
D) None of these
Show Answer
Answer:
Correct Answer: A
Solution:
Equation of circle touching both the axes will be $ x^{2}+y^{2}-2ax-2ay+a^{2}=0 $
Also it passes through (1, 2), therefore $ a=5,\ 1 $ .
Hence the equations of circles are $ x^{2}+y^{2}-2x-2y+1=0 $ and $ x^{2}+y^{2}-10x-10y+25=0 $ .
BETA
