Circle And System Of Circles Question 151
Question: The radical centre of the circles $ x^{2}+y^{2}+4x+6y=19,x^{2}+y^{2}=9 $ and $ x^{2}+y^{2}-2x-2y=5 $ will be
Options:
A) (1, 1)
B) (-1, 1)
C) (1, -1)
D) (0, 1)
Show Answer
Answer:
Correct Answer: A
Solution:
Radical axes are $ 4x+6y=10 $ or $ 2x+3y=5 $ ………….(i) $ 2x+2y=4 $ or $ x+y=2 $ ………….(ii)
Point of intersection of (i) and (ii) is (1, 1).
BETA
