Circle And System Of Circles Question 16
Question: If the centre of a circle is (2, 3) and a tangent is $ x+y=1 $ , then the equation of this circle is
[RPET 1985, 89]
Options:
A) $ {{(x-2)}^{2}}+{{(y-3)}^{2}}=8 $
B) $ {{(x-2)}^{2}}+{{(y-3)}^{2}}=3 $
C) $ {{(x+2)}^{2}}+{{(y+3)}^{2}}=2\sqrt{2} $
D) $ {{(x-2)}^{2}}+{{(y-3)}^{2}}=2\sqrt{2} $
Show Answer
Answer:
Correct Answer: A
Solution:
Find the radius by finding perpendicular distance from centre of the circle on the tangent and then find the equation of circle.
BETA
