Circle And System Of Circles Question 167
Question: Centre of the circle $ {{(x-3)}^{2}}+{{(y-4)}^{2}}=5 $ is
[MP PET 1988]
Options:
A) (3, 4)
B) $ (-3,\ -4) $
C) (4, 3)
D) $ (-4,\ -3) $
Show Answer
Answer:
Correct Answer: A
Solution:
It is obvious. We can see that the given equation is given in the form of $ {{(x-a)}^{2}}+{{(y-b)}^{2}}=r^2 $
So, the center of the circle will be (3,4)
BETA
