Circle And System Of Circles Question 171
Question: If the coordinates of one end of the diameter of the circle $ x^{2}+y^{2}-8x-4y+c=0 $ are (-3, 2), then the coordinates of other end are
[Roorkee 1995]
Options:
A) (5, 3)
B) (6, 2)
C) (1, -8)
D) (11, 2)
Show Answer
Answer:
Correct Answer: D
Solution:
Obviously the centre of the circle is (4, 2) which should be the middle point of the ends of diameter.
Hence the other end is (11, 2).
BETA
