Circle And System Of Circles Question 181
Question: The equation of the circle touching $ x=0,y=0 $ and $ x=4 $ is
[UPSEAT 2004]
Options:
A) $ x^{2}+y^{2}-4x-4y+16=0 $
B) $ x^{2}+y^{2}-8x-8y+16=0 $
C) $ x^{2}+y^{2}+4x+4y+4=0 $
D) $ x^{2}+y^{2}-4x-4y+4=0 $
Show Answer
Answer:
Correct Answer: D
Solution:
$ {{(x-2)}^{2}}+{{(y-2)}^{2}}=4 $
$ x^{2}+4-4x+y^{2}+4-4y=4 $
$ x^{2}+y^{2}-4x-4y+4=0 $ .
BETA
