Circle And System Of Circles Question 182
Question: The equation of the circle in the first quadrant which touches each axis at a distance 5 from the origin is
[MP PET 1997]
Options:
A) $ x^{2}+y^{2}+5x+5y+25=0 $
B) $ x^{2}+y^{2}-10x-10y+25=0 $
C) $ x^{2}+y^{2}-5x-5y+25=0 $
D) $ x^{2}+y^{2}+10x+10y+25=0 $
Show Answer
Answer:
Correct Answer: B
Solution:
The centre of the circle which touches each axis in first quadrant at a distance 5, will be (5, 5) and radius will be 5.
$ \therefore $ $ {{(x-h)}^{2}}+{{(y-k)}^{2}}=a^{2} $
$ \Rightarrow {{(x-5)}^{2}}+{{(y-5)}^{2}}={{(5)}^{2}} $
$ \Rightarrow x^{2}+y^{2}-10x-10y+25=0 $ .
BETA
