[MP PET 1996]
A) $ \pi a^{2} $
B) $ 2\pi a^{2} $
C) $ 4\pi a^{2} $
D) $ \frac{1}{2}\pi a^{2} $
Correct Answer: A
$ x^{2}+y^{2}-2ax=0 $ Obviously, radius of the circle is a.
Hence the area of triangle is $ \pi a^{2} $ .
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