Circle And System Of Circles Question 192
Question: Radius of the circle $ (x-1)(x-3)+(y-2)(y-4) $ $ =0 $ is
Options:
A) 2
B) $ \sqrt{2} $
C) 3
D) $ 2\sqrt{2} $
Show Answer
Answer:
Correct Answer: B
Solution:
Equation of the circle is $ (x-1)(x-3)+(y-2)(y-4)=0 $
So, radius $ =\frac{1}{2}\sqrt{{{(3-1)}^{2}}+{{(4-2)}^{2}}}=\frac{1}{2}\sqrt{8}=\frac{2\sqrt{2}}{2}=\sqrt{2} $ .
BETA
