Circle And System Of Circles Question 198
Question: The equation of the circle of radius 5 and touching the coordinate axes in third quadrant is
[EAMCET 2002]
Options:
A) $ {{(x-5)}^{2}}+{{(y+5)}^{2}}=25 $
B) $ {{(x+4)}^{2}}+{{(y+4)}^{2}}=25 $
C) $ {{(x+6)}^{2}}+{{(y+6)}^{2}}=25 $
D) $ {{(x+5)}^{2}}+{{(y+5)}^{2}}=25 $
Show Answer
Answer:
Correct Answer: D
Solution:
Since circle touches the co-ordinate axes in III quadrant.
$ \therefore $ Radius $ =-h=-k $ .
Hence $ h=k=-5 $
$ \therefore $ Equation of circle is $ {{(x+5)}^{2}}+{{(y+5)}^{2}}=25. $
BETA
