Circle And System Of Circles Question 200
Question: The circle $ x^{2}+y^{2}-3x-4y+2=0 $ cuts x-axis at
[Karnataka CET 2001; Pb. CET 2002]
Options:
A) $ (2,,0),(-3,,0) $
B) $ (3,,0),(4,,0) $
C) $ (1,,0),(-1,,0) $
D) $ (1,,0),(2,,0) $
Show Answer
Answer:
Correct Answer: D
Solution:
Given, equation of circle is $ x^{2}+y^{2}-3x-4y+2=0 $ and it cuts the x-axis.
$ \therefore $ $ x^{2}+0-3x+2=0 $ or $ x^{2}-3x+2=0 $ or $ (x-1),(x-2)=0 $ or $ x=1,,2. $
Therefore the points are (1,0) and (2, 0).
BETA
