Circle And System Of Circles Question 226
Question: The radius of the circle $ x^{2}+y^{2}+4x+6y+13=0 $ is
[Karnataka CET 2005]
Options:
A) $ \sqrt{26} $
B) $ \sqrt{13} $
C) $ \sqrt{23} $
D) 0
Show Answer
Answer:
Correct Answer: D
Solution:
Given equation of circle is $ x^{2}+y^{2}+4x+6y+13=0 $
Radius = $ \sqrt{g^{2}+f^{2}-c}=\sqrt{4+9-13}=0 $ .
BETA
