Circle And System Of Circles Question 255

Question: The equation of a diameter of circle $ x^{2}+y^{2}-6x+2y=0 $ passing through origin is

[RPET 1991; IIT 1989; MP PET 2002]

Options:

A) $ x+3y=0 $

B) $ x-3y=0 $

C) $ 3x+y=0 $

D) $ 3x-y=0 $

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Answer:

Correct Answer: A

Solution:

Centre (3, -1). Line through it and origin is $ x+3y=0 $ .