Circle And System Of Circles Question 270
Question: If the circles $ x^{2}+y^{2}=a^{2} $ and $ x^{2}+y^{2}-2gx+g^{2}-b^{2}=0 $ touch each other externally, then
Options:
A) $ g=ab $
B) $ g^{2}=a^{2}+b^{2} $
C) $ g^{2}=ab $
D) $ g=a+b $
Show Answer
Answer:
Correct Answer: D
Solution:
According to the condition,
$ \sqrt{{{(g-0)}^{2}}+{{(0-0)}^{2}}}=a+b\Rightarrow g=a+b $ .
BETA
