Circle And System Of Circles Question 275

Question: Radical axis of the circles $ 3x^{2}+3y^{2}-7x+8y+11=0 $ and $ x^{2}+y^{2}-3x-4y+5=0 $ is

[RPET 2001]

Options:

A) $ x+10y+2=0 $

B) $ x+10y-2=0 $

C) $ x+10y+8=0 $

D) $ x+10y-8=0 $

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Answer:

Correct Answer: B

Solution:

Radical axis of given circles is $ ( -\frac{7}{3}+3 ),x+( \frac{8}{3}+4 ),y+\frac{11}{3}-5=0 $

$ \Rightarrow $ $ 2x+20y-4=0 $

$ \Rightarrow $ $ x+10y-2=0 $ .