Circle And System Of Circles Question 279
Question: A circle which passes through origin and cuts intercepts on axes a and b, the equation of circle is
[RPET 1991]
Options:
A) $ x^{2}+y^{2}-ax-by=0 $
B) $ x^{2}+y^{2}+ax+by=0 $
C) $ x^{2}+y^{2}-ax+by=0 $
D) $ x^{2}+y^{2}+ax-by=0 $
Show Answer
Answer:
Correct Answer: A
Solution:
Centre is $ ( \frac{a}{2},\ \frac{b}{2} ) $ and radius $ =\sqrt{\frac{a^{2}+b^{2}}{4}} $
BETA
