Circle And System Of Circles Question 295
Question: The equation of the circumcircle of the triangle formed by the lines $ y+\sqrt{3}x=6,\ y-\sqrt{3}x=6, $ and $ y=0 $ , is
[EAMCET 1982]
Options:
A) $ x^{2}+y^{2}-4y=0 $
B) $ x^{2}+y^{2}+4x=0 $
C) $ x^{2}+y^{2}-4y=12 $
D) $ x^{2}+y^{2}+4x=12 $
Show Answer
Answer:
Correct Answer: C
Solution:
Solving $ y=0 $ and $ y+\sqrt{3}x=6 $ , we get $ (2\sqrt{3},,0) $ , only option (c) satisfies the co-ordinate.
BETA
