Circle And System Of Circles Question 298
Question: If the circles $ x^{2}+y^{2}-2ax+c=0 $ and $ x^{2}+y^{2}+2by+2\lambda =0 $ intersect orthogonally, then the value of $ \lambda $ is
Options:
c
- c
0
D) None of these
Show Answer
Answer:
Correct Answer: D
Solution:
Condition for circles to intersect orthogonally, $ 2(g_1g_2 + f_1f_2) = c_1 + c_2 $
$ \Rightarrow 0=c+2\lambda \Rightarrow \lambda =-\frac{c}{2} $ .
BETA
