Circle And System Of Circles Question 299
Question: The radical axis of the pair of circle $ x^{2}+y^{2}=144 $ and $ x^{2}+y^{2}-15x+12y=0 $ is
Options:
A) $ 15x-12y=0 $
B) $ 3x-2y=12 $
C) $ 5x-4y=48 $
D) None of these
Show Answer
Answer:
Correct Answer: C
Solution:
The radical axis of the circle $ S_1=0 $ and $ S_2=0 $ is $ S_1-S_2=0 $
$ \therefore \ (x^{2}+y^{2}-144)-(x^{2}+y^{2}-15x+12y)=0 $
$ \Rightarrow 15x-12y-144=0\Rightarrow 5x-4y=48 $ .
BETA
