Circle And System Of Circles Question 329
Question: The equation of the normal to the circle $ x^{2}+y^{2}-2x=0 $ parallel to the line $ x+2y=3 $ is
Options:
A) $ 2x+y-1=0 $
B) $ 2x+y+1=0 $
C) $ x+2y-1=0 $
D) $ x+2y+1=0 $
Show Answer
Answer:
Correct Answer: C
Solution:
Any line parallel to $ x+2y=3 $ is $ x+2y+\lambda =0 $ and for this to be a normal to the given circle, must pass through its centre (1, 0), i.e. $ \lambda =-1 $ . So, normal is $ x+2y-1=0 $ .
BETA
