Circle And System Of Circles Question 336
Question: The equation of the diameter of the circle $ x^{2}+y^{2}+2x-4y-11=0 $ which bisects the chords intercepted on the line $ 2x-y+3=0 $ is
Options:
A) $ x+y-7=0 $
B) $ 2x-y-5=0 $
C) $ x+2y-3=0 $
D) None of these
Show Answer
Answer:
Correct Answer: C
Solution:
We know that the diameter will be perpendicular to the chord because it bisects the chord.
Hence the equation of diameter is $ x+2y+k=0 $ ………….(i) But (i) also passes through the centre of circle $ (-1,\ 2) $ . Therefore, $ -1+4+k=0\Rightarrow k=-3 $ .
Hence the required equation is $ x+2y-3=0 $ .
BETA
