Circle And System Of Circles Question 350
Question: The area of triangle formed by the tangent, normal drawn at $ (1,\sqrt{3}) $ to the circle $ x^{2}+y^{2}=4 $ and positive x-axis, is
[IIT 1989; RPET 1997, 99; Kurukshetra CEE 1998]
Options:
A) $ 2\sqrt{3} $
B) $ \sqrt{3} $
C) $ 4\sqrt{3} $
D) None of these
Show Answer
Answer:
Correct Answer: A
Solution:
$ T\equiv x+\sqrt{3}y-4=0 $
Hence the required area $ =\frac{1}{2}\times 4\times \sqrt{3}=2\sqrt{3} $ .
BETA
