Circle And System Of Circles Question 370
Question: The equation of the tangent to the circle $ x^{2}+y^{2}=r^{2} $ at $ (a,b) $ is $ ax+by-\lambda =0 $ , where $ \lambda $ is
Options:
A) $ a^{2} $
B) $ b^{2} $
C) $ r^{2} $
D) None of these
Show Answer
Answer:
Correct Answer: C
Solution:
Equation of tangent is $ ax+by-r^{2}=0 $ .
BETA
