Circle And System Of Circles Question 373
Question: Which of the following is a point on the common chord of the circles $ x^{2}+y^{2}+2x-3y+6=0 $ and $ x^{2}+y^{2}+x-8y-13=0 $ Karnataka CET 2003]
Options:
A) (1, -2)
B) (1, 4)
C) (1, 2)
D) (1, -4)
Show Answer
Answer:
Correct Answer: D
Solution:
Equation of circles is $ S_1=x^{2}+y^{2}+2x-3y+6=0 $ ….. (i) $ S_2=x^{2}+y^{2}+x-8y-13=0 $ ….. (ii)
$ \therefore $ Equation of common chord is $ S_1-S_2=0 $
$ \Rightarrow x+5y+19=0 $ …..(iii) and out of the four given points only point (1, -4) satisfies it.
BETA
