Circle And System Of Circles Question 45
Question: The centre and radius of the circle $ 2x^{2}+2y^{2}-x=0 $ are
[MP PET 1984, 87]
Options:
A) $ ( \frac{1}{4},\ 0 ) $ and $ \frac{1}{4} $
B) $ ( -\frac{1}{2},\ 0 ) $ and $ \frac{1}{2} $
C) $ ( \frac{1}{2},\ 0 ) $ and $ \frac{1}{2} $
D) $ ( 0,\ -\frac{1}{4} ) $ and $ \frac{1}{4} $
Show Answer
Answer:
Correct Answer: A
Solution:
The circle is $ x^{2}+y^{2}-\frac{1}{2}x=0 $ . Centre $ (-g,\ -f)=( \frac{1}{4},\ 0 ) $ and $ R=\sqrt{\frac{1}{16}+0-0}=\frac{1}{4} $ .
BETA
